Digital Technology Binary Number Complements ڈیجیٹل ٹیکنالوجی میں بائنری نمبر کے اجزاء

 

Binary Number Complements






   According to the rule in the preceding section the 2,s complement of a binary number is formed by simply subtracting each digit (bit) of a number from the radix minus one and adding a 1 to the least significant bit. Since the radix in the binary number system is 2, each bit of the binary number is subtracted from 1.

The application of this rule is actually very simple every 1 in the number is changed to a 0 and every 0 to a 1. Then a 1 is added to the least significant bit of the number formed.

For instance the 2,s complement of 10110 is 01010, and the 2s complement of 11010 is 00110. Subtraction using the 2s complement system involves forming the 2s complement of the subtrahend and then adding this true complement to the minuend.

 

For instance,

      11011    11011

      -10100  =  +01100

      00111    1  00111

            ↓→carry is dropped

 

and second example is:

       11100      11100

      -10100  =  +01100

      11000   1  00111

            ↓→carry is dropped

 

Subtraction using the 1s complement system is also straightforward. The 1s complement of a binary number is formed by changing each 1 in the number to a 0 and each 0 in the number to a 1. For instance, the 1s complement of 10111 is 01000, and the 1s complement of 11000 is 00111.

When subtraction is performed in the 1s complement system, any end-around carry is added to the least significant bit.

 

 

 

For instance,

 

 11001      11001      and   11110   11110

   =     =        =    =

-10110      +01001     -01101      +10010

 00011     1  00010      10001   1  10000

      ↓→ 1         ↓→ 1

          00011                10001



بائنری نمبر کی تکمیل رداکس مائنس ون میں سے ہر ایک ہندسے (بٹ) کو صرف گھٹاتے ہوئے اور ایک کم سے کم اہم بٹ میں شامل کرکے تشکیل دی جاتی ہے۔ چونکہ بائنری نمبر سسٹم میں رڈکس 2 ہے ، لہذا بائنری نمبر کا ہر ایک حصہ 1 سے گھٹ جاتا ہے۔اس اصول کی اطلاق در حقیقت تعداد میں ہر 1 کو 0 میں اور 0 میں 1 میں تبدیل کر دیا گیا ہے۔ پھر ایک تشکیل کردہ تعداد میں کم سے کم اہم بٹ میں 1 شامل کیا جاتا ہے۔ مثال کے طور پر ، 10110 کی 2 ، s کی تکمیل 01010 ہے ، اور 11010 کی 2s کی تکمیل 00110 ہے۔ 2s تکمیلاتی نظام کا استعمال کرتے ہوئے گھٹاؤ میں subtrahend کی 2s تکمیل تشکیل دینا اور پھر من true منٹ میں اس حقیقی تکمیل کو شامل کرنا شامل ہے۔

 

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